p=-200p^2+12000p

Solution for p=-200p^2+12000p equation:

p=-200p^2+12000p

We move all terms to the left:

p-(-200p^2+12000p)=0

We get rid of parentheses

200p^2-12000p+p=0

We add all the numbers together, and all the variables

200p^2-11999p=0

a = 200; b = -11999; c = 0;
Δ = b2-4ac
Δ = -119992-4·200·0
Δ = 143976001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{143976001}=11999$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11999)-11999}{2*200}=\frac{0}{400}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11999)+11999}{2*200}=\frac{23998}{400}
=59+199/200
$